Question

一道ACM题目.看看代码,为什么检测的时候总WRONG ANSWER.

1326. Soundex
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Time Limit: 1.0 Seconds Memory Limit: 65536K
Total Runs: 4945 Accepted Runs: 1732 Multiple test files

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Soundex coding groups together words that appear to sound alike based on their spelling. For example, "can" and "khawn", "con" and "gone" would be equivalent under Soundex coding.
Soundex coding involves translating each word into a series of digits in which each digit represents a letter:

1 represents B, F, P, or V
2 represents C, G, J, K, Q, S, X, or Z
3 represents D or T
4 represents L
5 represents M or N
6 represents R

The letters A, E, I, O, U, H, W, and Y are not represented in Soundex coding, and repeated letters with the same code digit are represented by a single instance of that digit. Words with the same Soundex coding are considered equivalent.
Each line of input contains a single word, all upper case, less than 20 letters long. For each line of input, produce a line of output giving the Soundex code.

Sample Input
KHAWN
PFISTER
BOBBY

Output for Sample Input
25
1236
11

我写的代码如下:
#include <iostream>
#include <string>
using namespace std;

int main()
{
for(int K=0;K<1002;K++)
{
char a[30];
cin>>a;
for(int i=0;i<strlen(a);i++)
{
if((a[i]=='B'||a[i]=='F'||a[i]=='P'||a[i]=='V')&&(a[i+1]!='B'&&a[i+1]!='F'&&a[i+1]!='P'&&a[i+1]!='V'))
cout<<1;
if((a[i]=='C'||a[i]=='G'||a[i]=='J'||a[i]=='K'||a[i]=='Q'||a[i]=='S'
||a[i]=='X'||a[i]=='Z')&&(a[i+1]!='C'&&a[i+1]!='G'&&a[i+1]!='J'&&a[i+1]!='K'&&a[i+1]!='Q'&&a[i+1]!='S'
&&a[i+1]!='X'&&a[i+1]!='Z'))
cout<<2;
if((a[i]=='D'||a[i]=='T')&&(a[i+1]!='D'&&a[i+1]!='T'))
cout<<3;
if(a[i]=='L'&&a[1+1]!='L')
cout<<4;
if((a[i]=='M'||a[i]=='N')&&(a[i+1]!='M'&&a[i+1]!='N'))
cout<<5;
if(a[i]=='R'&&a[i+1]!='R')
cout<<6;

}
cout<<endl;
}
return 0;
}
代表的数字相同就只要一个

Answer 1

我英文不好 题目意思是连续相同的字母只要一个 还是只要代表的数字相同就只要一个啊

Answer 2

#include<iostream>
#include<string>
using namespace std;
int main( )
{
while(1)
{
int n=0; char c; string answer=