Question

一道C语言的改错题

#include<stdio.h>
void main()
{
int year,leap;
scanf("%d",year);
if((year%4=0&year%100!=0)OR(year%400==0))
leap=1;
else
leap=0;
if(leap=1)
printf("%d is a leap year!\n",year);
else
printf("%d is not aleap year!\n",year);
}
呵呵，分很少，大家不要嫌弃，相互学习嘛。

Answer 1

#include<stdio.h>
void main()
{
int year,leap;
scanf("%d",&year); // year --> &year
if((year%4==0&year%100!=0)|(year%400==0)) // =是复制语句， ==才是判断语句,C语言中没有OR， 表示"或" 使用“|”
leap=1;
else
leap=0;
if(leap==1) //=是复制语句， ==才是判断语句
printf("%d is a leap year!\n",year);
else
printf("%d is not aleap year!\n",year);
}

两处错误都在语句中if((year%4=0&year%100!=0)OR(year%400==0))
1. year%4=0 应该为year%4 == 0； =是复制语句， ==才是判断语句
2. OR C语言中没有OR， 表示"或" 使用“|”
所以

Answer 2

1、这是个计算闰年的程序
2、 if((year%4=0&year%100!=0)OR(year%400==0))
应该是year%4==0

Answer 3

第一处错误:scanf("%d",year);->scanf("%d",&year);
第二处错 误:if((year%4=0&year%100!=0)OR(year%400==0))->if((year%4==0&&year%100!=0)||(year%40 0==0))
第三处错误:if(leap=1)->if(leap==1)

Answer 4

scanf("%d",&year);
if((year%4==0 && year%100!=0) || (year%400==0))