设f(x)是定义在r上的奇函数,且满足f(x+2)=-f(x) 当0=《x《=1时 f(x)=x则f(7.5)=
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f(-0.5) = -f(0.5) = -0.5 ( f is odd)
f(x+2) = -f(x)
put x = -0.5
f(1.5) = -f(-0.5) = 0.5
put x = 1.5
f(3.5) = -f(1.5) = -0.5
put x = 3.5
f(5.5) = -f(3.5) = 0.5
put x = 5.5
f(7.5) = -f(5.5) = -0.5 #
f(x+2) = -f(x)
put x = -0.5
f(1.5) = -f(-0.5) = 0.5
put x = 1.5
f(3.5) = -f(1.5) = -0.5
put x = 3.5
f(5.5) = -f(3.5) = 0.5
put x = 5.5
f(7.5) = -f(5.5) = -0.5 #
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