Question

C++上机实验时出现 mismatch in formal parameter list 的错误是为什么啊 ？？？求解！！谢谢了

以下是程序：
#include<iostream>
#include<string>
using namespace std;
class Student
{public:
void get_value();
void display();
protected:
int num;
char name[20];
char sex;
};

void Student::get_value()
{cin>>num>>name>>sex;}

void Student::display()
{cout<<"num:"<<num<<endl;
cout<<"name:"<name<<endl;
cout<<"sex:"<<sex<<endl;}

class Student1:protected Student
{public:
void get_value_1();
void display1();
private:
int age;
char addr[30];
};
void Student1::get_value_1()
{get_value();
cin>>age>>addr;
}

void Student1::display1()
{cout<<"num:"<<num<<endl;
cout<<"name:"<<name<<endl;
cout<<"sex:"<<sex<<endl;
cout<<"age:"<<age<<endl;
cout<<"address:"<<addr<<endl;
}

int main()
{Student1 stud1;
stud1.get_value_1();
stud1.dispaly1();
//stud1.num=10023;
return 0;}

Answer 1

这样写就行了。
#include<iostream>
#include<string>
using namespace std;
class Student
{
public:
void get_value();
void display();
protected:
int num;
string name;
char sex;
};

void Student::get_value()
{cin>>num>>name>>sex;}

void Student::display()
{cout<<"num:"<<num<<endl;
cout<<"name:"<<name<<endl;
cout<<"sex:"<<sex<<endl;}

class Student1:protected Student
{public:
void get_value_1();
void display1();
private:
int age;
string addr;
};
void Student1::get_value_1()
{get_value();
cin>>age>>addr;
}

void Student1::display1()
{cout<<"num:"<<num<<endl;
cout<<"name:"<<name<<endl;
cout<<"sex:"<<sex<<endl;
cout<<"age:"<<age<<endl;
cout<<"address:"<<addr<<endl;
}

int main()
{Student1 stud1;
stud1.get_value_1();
stud1.display1();
//stud1.num=10023;
return 0;}

第十八行少一个<符号。
cout<<"name:"<name<<endl;