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F(x,y)存在二阶连续偏导数且对 y 的偏导数不为 0,求 y 的二阶导数?
将等式 F(x,y)=0 两边对 x 求导:∂F/∂x +(∂F/∂y)(dy/dx)=0,∴ y'=dy/dx=-(∂F/∂x)/(∂F/∂y);
y"=dy'/dx=d[-(∂F/∂x)/(∂F/∂y)]/dx
=-[(∂²F/∂x²)*(∂F/∂y)-(∂F/∂x)*(∂²F/∂x² +∂²F/∂x∂y*y')]/(∂F/∂y)²
=-[(∂²F/∂x²)(∂F/∂y)-(∂F/∂x)(∂²F/∂x²) +(∂F/∂x)²*(∂²F/∂x∂y)/(∂F/∂y)]/(∂F/∂y)²
=-[(∂²F/∂x²)-(∂F/∂y)(∂F/∂x)(∂²F/∂x²) +(∂F/∂x)²*(∂²F/∂x∂y)]/(∂F/∂y)³;
将等式 F(x,y)=0 两边对 x 求导:∂F/∂x +(∂F/∂y)(dy/dx)=0,∴ y'=dy/dx=-(∂F/∂x)/(∂F/∂y);
y"=dy'/dx=d[-(∂F/∂x)/(∂F/∂y)]/dx
=-[(∂²F/∂x²)*(∂F/∂y)-(∂F/∂x)*(∂²F/∂x² +∂²F/∂x∂y*y')]/(∂F/∂y)²
=-[(∂²F/∂x²)(∂F/∂y)-(∂F/∂x)(∂²F/∂x²) +(∂F/∂x)²*(∂²F/∂x∂y)/(∂F/∂y)]/(∂F/∂y)²
=-[(∂²F/∂x²)-(∂F/∂y)(∂F/∂x)(∂²F/∂x²) +(∂F/∂x)²*(∂²F/∂x∂y)]/(∂F/∂y)³;
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