Question

求数学题答案

Answer 1

解：由已知得：∠F=2∠ B—90°又∵∠F=∠HAF+∠GCF ∠B=∠BAH+∠GCB ∴∠HAF+∠GCF=2（∠BAH+∠GCB）—90° 又∵∠BAH=2∠HAF ∠GCB=0.5∠GCF ∴∠HAF+∠GCF=4∠HAF +∠GCF—90° ∴∠HAF=30°故：∠BAH的度数为60°.

Answer 2

60度祝你学习进步

Answer 3

自己答，成功靠自己，爱拼会赢

Answer 4

解：由已知得：∠F=2∠ B—90°又∵∠F=∠HAF+∠GCF ∠B=∠BAH+∠GCB ∴∠HAF+∠GCF=2（∠BAH+∠GCB）—90° 又∵∠BAH=2∠HAF ∠GCB=0.5∠GCF ∴∠HAF+∠GCF=4∠HAF +∠GCF—90° ∴∠HAF=30°故：∠BAH的度数为60°.