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一道数学题,帮帮忙
1111______+______________+______________+............________________ab(a+1)(b+1)(a+2...
1 1 1 1
______+______________+______________+............________________
ab (a+1)(b+1) (a+2)(b+2) (a+2008)(b+2008)
其中a=2,b=1 展开
______+______________+______________+............________________
ab (a+1)(b+1) (a+2)(b+2) (a+2008)(b+2008)
其中a=2,b=1 展开
1个回答
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a=2,b=1
所以原式=1/1*2+1/2*3+1/3*4+……+1/2009*2010
=1-1/2+1/2-1/3+1/3-1/4+……+1/2009-1/2010
=1-1/2010
=2009/2010
所以原式=1/1*2+1/2*3+1/3*4+……+1/2009*2010
=1-1/2+1/2-1/3+1/3-1/4+……+1/2009-1/2010
=1-1/2010
=2009/2010
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