因式分解:(1)x2-3xy-10y2+x+9y-2;(2)x3-11x2+31x-21
展开全部
(1)原式=(x+2y)(x-5y)+2x+4y-x+5y-2
=(x+2y)(x-5y)+2(x+2y)-(x-5y+2)
=(x+2y)(x-5y+2)-(x-5y+2)
=(x+2y-1)(x-5y+2);
(2)镇裤原式=(x3-1)-(11x3-31x+20)御山简
=(x-1)(x2+x+1)-(11x-20)(x-1)
=(x-1)(x2+x+1-11x+20)
=(x-1)(x2-10x+21)唯桥
=(x-1)(x-3)(x-7).
=(x+2y)(x-5y)+2(x+2y)-(x-5y+2)
=(x+2y)(x-5y+2)-(x-5y+2)
=(x+2y-1)(x-5y+2);
(2)镇裤原式=(x3-1)-(11x3-31x+20)御山简
=(x-1)(x2+x+1)-(11x-20)(x-1)
=(x-1)(x2+x+1-11x+20)
=(x-1)(x2-10x+21)唯桥
=(x-1)(x-3)(x-7).
本回答被提问者采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询