先化简，再求值：（x+2x2?2x-x?1x2?4x+4）÷x?4x3?2x2，x=-2
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原式=（
-
）÷
=
×
=
×
=
×
=
，
当x=-2时，原式=
=
．
| x+2 |
| x(x?2) |
| x?1 |
| (x?2)2 |
| x?4 |
| x2(x?2) |
=
| (x+2)(x?2)?x(x?1) |
| x(x?2)2 |
| x2(x?2) |
| x?4 |
=
| x2?4?x2+x |
| x(x?2)2 |
| x2(x?2) |
| x?4 |
=
| x?4 |
| x(x?2)2 |
| x2(x?2) |
| x?4 |
=
| x |
| x?2 |
当x=-2时，原式=
| ?2 |
| ?2?1 |
| 2 |
| 3 |
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