高一数学，过程要详细 15
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[sin(θ-5π)cos(-π/2-θ)cos(8π-θ)]/[sin(π/2+θ)cos(-π/2+θ)sin(π-θ)]
={sin(-4π+θ-π)sin[π/2-(-π/2-θ)]cos(8π-θ)}/{cos[π/2-(π/2+θ)]sin[π/2-(-π/2+θ)]sin(π-θ)}
=[sin(θ-π)sin(π+θ)cos(-θ)]/[cos(-θ)sin(π-θ)sin(π-θ)]
=[(-sinθ)(-sinθ)cosθ]/(cosθsinθsinθ)
=(sinθsinθcosθ)/(cosθsinθsinθ)
=1
={sin(-4π+θ-π)sin[π/2-(-π/2-θ)]cos(8π-θ)}/{cos[π/2-(π/2+θ)]sin[π/2-(-π/2+θ)]sin(π-θ)}
=[sin(θ-π)sin(π+θ)cos(-θ)]/[cos(-θ)sin(π-θ)sin(π-θ)]
=[(-sinθ)(-sinθ)cosθ]/(cosθsinθsinθ)
=(sinθsinθcosθ)/(cosθsinθsinθ)
=1
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