分式的计算
1个回答
展开全部
=(x+y)/[x(x-y)] - (x+y)²(x-y)²/x * 1/(x-y)³
=(x+y)/[x(x-y)] - (x+y)²/x²* 1/(x-y)
=(x²+xy)/[x²(x-y)] - (x+y)²/[x²(x-y)]
=(x²+xy-x²-2xy-y²)/[x²(x-y)]
=-(xy+y²)/[x²(x-y)]
=-(xy+y²)/(x³-x²y)]
=(x+y)/[x(x-y)] - (x+y)²/x²* 1/(x-y)
=(x²+xy)/[x²(x-y)] - (x+y)²/[x²(x-y)]
=(x²+xy-x²-2xy-y²)/[x²(x-y)]
=-(xy+y²)/[x²(x-y)]
=-(xy+y²)/(x³-x²y)]
本回答由提问者推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
