Question

轮播图片跳转到指定链接

src="//img11.360buyimg.com/cms/g17/M00/02/06/rBEbSVNx8KMIAAAAAAI9ue9B8hEAAAoiQOLW-UAAj3R035.jpg" title="" width="1920" height="550" alt="" />
</dt>
</dl>
<dl background="" ref="" class="show" style="width: 1920px; height: 100%; float: left;">
<dt>
<img src="//img10.360buyimg.com/imgzone/jfs/t2713/288/1274239302/543107/92daf0ef/57395a97N492094f5.jpg" title="" width="1920" height="550" alt="" />
我想为这个图片加一个跳转链接，例如跳转到baidu.com，代码需要怎么写，小白麻烦大神指导
</dt>
</dl>
<dl background="" ref="" style="width: 1920px; height: 100%; float: left;">
</dl>
</div>

Answer 1

图片跳转代码：<a href="链接跳转地址" target="_blank"><img src="图片地址"/></a>

所以你这个就是<a href="baidu.com" target="_blank"><img src="//img10.360buyimg.com/imgzone/jfs/t2713/288/1274239302/543107/92daf0ef/57395a97N492094f5.jpg" title="" width="1920" height="550" alt="" /> </a>