已知log（2）[log（3)(log(4) x)] = log(3) [log(4) (log(2) y)]=0,求x+y的值
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log（2)[log（3)(log(4) x)] = 0
log（3)(log(4) x) = 1
log(4) x = 3
x = 64
log(3)[log(4) (log(2) y)] = 0
log(4)(log(2) y) = 1
log(2) y = 4
y = 16
所以 x + y = 80
log（3)(log(4) x) = 1
log(4) x = 3
x = 64
log(3)[log(4) (log(2) y)] = 0
log(4)(log(2) y) = 1
log(2) y = 4
y = 16
所以 x + y = 80
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