Question

shell if 多条件 与case语句结合出现问题

脚本如下：

#!/bin/bash
set -x
echo "please choose one of name:"
echo jack
echo may
echo mary
echo
read name
if [ "$name"="jack" -o "$name"="may" -o "$name"="mary" ]
then
case "$name" in
jack | JACK )
echo "sex: man"
echo "age: 29"
echo "phone NO.:123456"
;;
mary | MARY )
echo "sex: woman"
echo "age: 33"
echo "phone NO.:654321"
;;
may | MAY )
echo "sex: woman"
echo "age: 21"
echo "phone NO.:13579"
;;
esac

else
echo "no such people"
fi
exit 0

当输入的为jack，may，mary时，输出正确，但是当输入的字符串为abc时，直接跳出，不会提示“no such people”，请问我的脚本哪里出错了呢？

Answer 1

if [ "$name" = "jack" -o "$name" = "may" -o "$name" = "mary" ] 注意数据间的等号不要与数据连在一起，加上空格分开，不然会当成一个整体，不会进行比较