Question

比较基础的物理力学问题 ！急救，很急。谢谢大家！

一个1.50kg 的箱子在无摩擦的平面上向右以8.00m/s匀速运动。 在t=0s 时一个水平的力施加在箱子上。 这个力方向向左，力的值遵循F（t）=(6.00N/s^2)t^2 这条公式.

（1）由t=0开始，在箱子的速度减至0时，箱子的位移是多少？

（2）在t=4.5s时，箱子的速度是多少？
原题：A 1.50 kg box is moving to the right with speed 8.00 m/s on a horizontal, frictionless surface. At t = 0 a horizontal force is applied to the box. The force is directed to the left and has magnitude F(t)=( 6.00 N/s^2)t^2

（1）What distance does the box move from its position at t=0 before its speed is reduced to zero?

(2)If the force continues to be applied, what is the velocity of the box at 4.50s?

Answer 1

有答案没？
我计算的结果是
（1）10.90m
（2）113.5m/s，向左