高中数学定积分.请问这八道题怎么做(如图),求有过程,谢谢!!!
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(1)原式=(sinx+cosx)|(0,π/2)
=1+0-0-1
=0
(2)闭李闭原式=(e^x-2ln|x|)|(1,2)
=e^2-2ln2-e+0
=e^2-e-ln4
(3)原式=[(2/3)*x^(3/2)-(1/3)*x^3]|(0,1)
=2/3-1/3-0+0
=1/3
(4)原式=(x^2+1/x-ln|x|)|(1,3)
=9+1/轿裂3-ln3-1-1+0
=22/3-ln3
(5)原式=(1/2)*∫(0,π/2) (1-cosx)dx
=(1/2)*(x-sinx)|(0,π/2)
=(1/2)*(π/2-1-0+0)
=π/4-1/2
(6)原式=ln|x-1||(2,e+1)
=1-0
=1
(7)原式=(1/2)*e^(2x)|(0,1)
=(1/2)*e^2-1/2
=(e^2-1)/2
(8)原式=(1/2)*sin2x|(π/6,π/4)
=(1/2)*(1-√扰租3/2)
=1/2-√3/4
=1+0-0-1
=0
(2)闭李闭原式=(e^x-2ln|x|)|(1,2)
=e^2-2ln2-e+0
=e^2-e-ln4
(3)原式=[(2/3)*x^(3/2)-(1/3)*x^3]|(0,1)
=2/3-1/3-0+0
=1/3
(4)原式=(x^2+1/x-ln|x|)|(1,3)
=9+1/轿裂3-ln3-1-1+0
=22/3-ln3
(5)原式=(1/2)*∫(0,π/2) (1-cosx)dx
=(1/2)*(x-sinx)|(0,π/2)
=(1/2)*(π/2-1-0+0)
=π/4-1/2
(6)原式=ln|x-1||(2,e+1)
=1-0
=1
(7)原式=(1/2)*e^(2x)|(0,1)
=(1/2)*e^2-1/2
=(e^2-1)/2
(8)原式=(1/2)*sin2x|(π/6,π/4)
=(1/2)*(1-√扰租3/2)
=1/2-√3/4
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