画圈的题求解
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(1)
lim(x->2) (x^2+6x-5)
=4+12-5
=11
(2)
lim(x->-3) (x^2-9)/(x^2+5x+6)
=lim(x->-3) (x+3)(x-3)/[(x+3)(x+2)]
=lim(x->-3) (x-3)/(x+2)
=-6/(-1)
=6
(5)
lim(x->2) [√(x-1) -1] /(x-2)
=lim(x->2) (x-2)/{[√(x-1) +1].(x-2)}
=lim(x->2) 1/[√(x-1) +1]
= 1/[ 1+1]
=1/2
lim(x->2) (x^2+6x-5)
=4+12-5
=11
(2)
lim(x->-3) (x^2-9)/(x^2+5x+6)
=lim(x->-3) (x+3)(x-3)/[(x+3)(x+2)]
=lim(x->-3) (x-3)/(x+2)
=-6/(-1)
=6
(5)
lim(x->2) [√(x-1) -1] /(x-2)
=lim(x->2) (x-2)/{[√(x-1) +1].(x-2)}
=lim(x->2) 1/[√(x-1) +1]
= 1/[ 1+1]
=1/2
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