Question

求解这道高数极限题！

求解这道高数极限题！求解，尤其是第二道！

Answer 1

望采悉辩正睁悔纳谢谢灶衡啦

Answer 2

最枣亮佳答案
lim(x→π/凳陵宽2)(tanx)^sin2x
=e^[lim(x→π/2)sin2xlntanx
=e^[lim(x→π/2)sin2x/(1/lntanx)]
=e^[lim(x→π/2)2cos2xtanx/sec^2x]
=e^[lim(x→π/2)2cos2xsinxcosx]
=e^[lim(x→π/2)cos2xsin2x]
=e^[lim(x→π/2)1/2sin4x]
=e^[1/汪闹2sin(4×π/2)]
=e^0