Question

问2道SAT数学题目。

（1）If 537(的102次方) were calculated, it would have 279 digits. What would the digit farthest to the right be(the ones digit)?
答案：A 1 B 3 C 4 D 7 E 9
(2) A performance was rated on a 3-point scale by an audience.A rating of 1 was given by 30% of the audience, a rating of 2 by 60%,and a rating of 3 by 10%. To the nearest tenth,what was the average of the ratings?
答案：A 1.2 B 1.5 C 1.8 D 2.0 E 2.2
请详细解答！最主要是翻译。

Answer 1

1E （If 537(的102次方) were calculated, it would have 279 digits. What would the digit farthest to the right be(the ones digit)?如果求到537的102次方，会有279位数，那个位数是多少） （这个的做法瞎蒙的，数学已经远去，我把102分解成3*2*17， 7的三次方后个位是3这个3再平方，就成了9，最后就求9的17次方，然后我想就每次平方后面都是1，最后就剩下一个9没有平方，是不是就是9了~~这个确实是蒙的~~）
2C A performance was rated on a 3-point scale by an audience.A rating of 1 was given by 30% of the audience, a rating of 2 by 60%,and a rating of 3 by 10%. To the nearest tenth,what was the average of the ratings?观众用3分为满分的方式平价一个表演，有30%的人平价1分，60%的人平价2分，10%的人平价3分，求平价平均分。 0.3*1+0.6*2+0.1*3

Answer 2

1.B 2.C

Answer 3

(1)C,(2)A