Question

python遍历excel工作表并合并单元格

Answer 1

代码如下:
# -*- coding: utf-8 -*-import xlrdimport uuidclass Student():
def __init__(self, id, **kw):
self.id = id
for k, v in kw.items():
setattr(self, k, v)

def __str__(self):
return '%s(id=%s,column1=%s,column2=%s,column3=%s,column4=%s)' \ % (
self.__class__.__name__, self.id, self.column1, self.column2, self.column3,
self.column4)def read_excel():
# 打开文件
workbook = xlrd.open_workbook(r'py.xlsx')
# 获取所有sheet
print('打印所有sheet:', workbook.sheet_names())

sheet2 = workbook.sheet_by_index(0) # sheet索引从0开始
rows_num = sheet2.nrows
cols_num = sheet2.ncols for r in range(rows_num):
# 一行数据的实体类
entity_dict = {}
for c in range(cols_num):
cell_value = sheet2.row_values(r)[c]
# print('第%d行第%d列的值：[%s]' % (r, c, sheet2.row_values(r)[c]))
if (cell_value is None or cell_value == ''):
cell_value = (get_merged_cells_value(sheet2, r, c))
# 构建Entity
the_key = 'column' + str(c + 1);
# 动态设置各属性值
entity_dict[the_key] = cell_value
entity_dict['id'] = getUUID()
stu = Student(**entity_dict)
print(stu)def get_merged_cells(sheet):
"""
获取所有的合并单元格，格式如下：
[(4, 5, 2, 4), (5, 6, 2, 4), (1, 4, 3, 4)]
(4, 5, 2, 4) 的含义为：行 从下标4开始，到下标5（不包含） 列 从下标2开始，到下标4（不包含），为合并单元格
:param sheet:
:return:
"""
return sheet.merged_cellsdef get_merged_cells_value(sheet, row_index, col_index):
"""
先判断给定的单元格，是否属于合并单元格；
如果是合并单元格，就返回合并单元格的内容
:return:
"""
merged = get_merged_cells(sheet)
for (rlow, rhigh, clow, chigh) in merged:
if (row_index >= rlow and row_index < rhigh):
if (col_index >= clow and col_index < chigh):
cell_value = sheet.cell_value(rlow, clow)
# print('该单元格[%d,%d]属于合并单元格，值为[%s]' % (row_index, col_index, cell_value))
return cell_value break
return Nonedef getUUID():
return uuid.uuid1().hexif __name__ == "__main__":
read_excel()