Question

Python 怎么将列表类字典组字符串转换为列表？

有如下一组字符串，
[{"id":100220748688221696701923815,"ts":1614576522050,"tradeId":7500734,"amount":1152.43,"price":0.01852,"direction":"sell"}]

怎么将他转换成字典类列表，或者其他方法，我需要直接读取ID TS tradeID 项目
注意 最后一项direction 项目不像其他的没有冒号

Answer 1

如果是你发的那一串肯定是可以用json loads的，如果不能，发下原文字符串。

追问

字符串如下，因为字数限制，我附件了图片分别是EVAL 和JSON.LOADS的报错

[{"id":100569603575223726729043332,"ts":1614588720703,"tradeId":3853176,"amount":8.69,"price":19.6403,"direction":CCR}]

追答

我就说嘛，这个是为最后的CCR需要特殊处理的，要在字符串中加入引号才能用jsonloads

以前写过类似的，你看看

Answer 2

list1=[{"id":100220748688221696701923815,"ts":1614576522050,"tradeId":7500734,"amount":1152.43,"price":0.01852,"direction":"sell"}]
list_new=[]
d=list1[0]
print(d)
for key in d:
list_new.append(key)
list_new.append(d[key])
print(list_new)

追问

可能有一些没说清楚，字符串是通过
compressData = ws.recv()
result = gzip.decompress(compressData).decode('utf-8')
解析出来，通过查找截取字符后生成
[{"id":100220748688221696701923815,"ts":1614576522050,"tradeId":7500734,"amount":1152.43,"price":0.01852,"direction":"sell"}] 列表样的字符串
我用了json.loads 和EVAL 但是都不能变成list，

Answer 3

不知理解得对不对，你看看：

test = [
[{'id':11,
'ts':12,
'tradeId':13,
'amount':14,
'price':15,
'direction':'1'
}],
[{'id':21,
'ts':22,
'tradeId':23,
'amount':24,
'price':25,
'direction':'2'
}],
[{'id':31,
'ts':32,
'tradeId':33,
'amount':34,
'price':35,
'direction':'3'
}],
]
result = {'id':[],'ts':[],'tradeId':[],'amount':[],'price':[],'direction':[]}

for row in test:
for sub_row in row:
result['id'].append(sub_row['id'])
result['ts'].append(sub_row['ts'])
result['tradeId'].append(sub_row['tradeId'])
result['amount'].append(sub_row['amount'])
result['price'].append(sub_row['price'])
result['direction'].append(sub_row['direction'])

由于太复杂的功能不会用列表推导式，所以就做成循环了，即最后是一个字典，字典中的值是列表：