Question

找规律填数4,10,16,22,28,(),(),46？

Answer 1

4+6=10，10+6=16，16+6=22，22+6=28，28+6=34，34+6=40，40+6=46，括号里的数是34和40，每个数字一次加6即可。

Answer 2

4,10,16,22,28,(34),(40),46，两数之间相差6

Answer 3

递进6
4+6=10
10+6=16
16+6=22
22+6=28
28+6=（34）
34+6=（40）
40+6=46

Answer 4

完完全全教授诈骗！为什么不能填 π 和 e 并且第 9 项为虚数 i ？有谁能告诉我？
an=4(n-2)(n-3)(n-4)(n-5)(n-6)(n-7)(n-8)(n-9)/[(1-2)(1-3)(1-4)(1-5)(1-6)(1-7)(1-8)(1-9)]
+10(n-1)(n-3)(n-4)(n-5)(n-6)(n-7)(n-8)(n-9)/[(2-1)(2-3)(2-4)(2-5)(2-6)(2-7)(2-8)(2-9)]
+16(n-1)(n-2)(n-4)(n-5)(n-6)(n-7)(n-8)(n-9)/[(3-1)(3-2)(3-4)(3-5)(3-6)(3-7)(3-8)(3-9)]
+22(n-1)(n-2)(n-3)(n-5)(n-6)(n-7)(n-8)(n-9)/[(4-1)(4-2)(4-3)(4-5)(4-6)(4-7)(4-8)(4-9)]
+28(n-1)(n-2)(n-3)(n-4)(n-6)(n-7)(n-8)(n-9)/[(5-1)(5-2)(5-3)(5-4)(5-6)(5-7)(5-8)(5-9)]
+π (n-1)(n-2)(n-3)(n-4)(n-5)(n-7)(n-8)(n-9)/[(6-1)(6-2)(6-3)(6-4)(6-5)(6-7)(6-8)(6-9)]
+e (n-1)(n-2)(n-3)(n-4)(n-5)(n-6)(n-8)(n-9)/[(7-1)(7-2)(7-3)(7-4)(7-5)(7-6)(7-8)(7-9)]
+46 (n-1)(n-2)(n-3)(n-4)(n-5)(n-6)(n-7)(n-9)/[(8-1)(8-2)(8-3)(8-4)(8-5)(8-6)(8-7)(8-9)]
+i (n-1)(n-2)(n-3)(n-4)(n-5)(n-6)(n-7)(n-8)/[(9-1)(9-2)(9-3)(9-4)(9-5)(9-6)(9-7)(9-8)]

Answer 5

规律:每相邻的两个数相差6，
∴4，10，16，22，28，34，4O，46