(-x-y+2y)的平方是多少?
2个回答
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(x y)的平方-(x y)的平方=[(x y)(x y)][(x y)-(x y)]=(x y x y)(x y y y)= 2x * 2y = 4xy
(x y)的平方-(x y)的平方=[(x y)(x y)][(x y)-(x y)]= 2x×2y = 4xy
(x y)的平方-(x y)的平方= (x y x y) (x y x y) = 2x * 2y = 4xy。如果不理解,请接受。谢谢大家!
(x y)-(x y) = x y 2xy-(x y 2xy) = 4xy这是平方和的公式(x y)=(x y)*(x y)= x * x x * y y y * y = x 2xy y(x y)=(x y)
= {(x y)(x-y)} * {(x y)-(x-y)} = 2x * 2y = 4xy
(x y)的平方-(x y)的平方=[(x y)(x y)][(x y)-(x y)]= 2x×2y = 4xy
(x y)的平方-(x y)的平方= (x y x y) (x y x y) = 2x * 2y = 4xy。如果不理解,请接受。谢谢大家!
(x y)-(x y) = x y 2xy-(x y 2xy) = 4xy这是平方和的公式(x y)=(x y)*(x y)= x * x x * y y y * y = x 2xy y(x y)=(x y)
= {(x y)(x-y)} * {(x y)-(x-y)} = 2x * 2y = 4xy
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