Question

求解一道数学题！！！！在线等！！！挺急的！！！！

Answer 1

1<=x<=3/2

g(x) = 4x-8(3/2-x)x-6=0
8x^2-8x-6=0
4x^2-4x-3=0
(2x+1)(2x-3)=0
x1=3/2

3/2<x<=2
g(x) = 4x-8x(x-3/2)-6=0
8x^2-16x+6=0
4x^2-8x+3=0
(2x-1)(2x-3)=0
无解

2<x<=3
1<x/2<=3/2
f(x) = 1/2 * f(x/2) = 1/2 * (4-8(3/2-x/2)) = 2-6+2x=2x-4
g(x) = x(2x-4)-6=2x^2-4x-6=0
x^2-2x-3=0
(x-3)(x+1)=0

x2 = 3

3<x<=4
3/2<x<=2
f(x)=1/2*f(x/2) = 1/2*(4-8(x/2-3/2)) = 2-2x+6=8-2x
g(x)=x(8-2x)-6=0
x^2-4x+3=0
(x-3)(x-1)=0
此区间无解
4<x<=6
1<x/4<=3/2
f(x)=1/4f(x/4) = 1/4*(4-8(3/2-x/4)) = 1-3+x/2=x/2-2
g(x)=x(x/2-2)-6=0
x^2-4x-12=0
(x-6)(x+2)=0
x3=6

6<x<=8
3/2<x/4<=2
f(x)=1/4f(x/4) = 1/4*(4-8(x/4-3/2)) = 1-x/2+3=4-x/2
g(x) = x(4-x/2)-6=0
x^2-8x+12=0
(x-2)(x-6)=0
无解

所以综上
x1=3/2
x2=3
x3=6
x1+x2+x3=21/2

Answer 2

你好，这道题是改编自这道题：

最后答案可以参考这个思路算出来！！

麻烦请采纳！

追问

区间[4,8]的具体解题步骤是什么，6是怎么算的？

追答

你能采纳吗

Answer 3

我的计算结果为1.5、3、6，所以和为10.5

追问

解题过程是怎么样的，能把过程告诉我吗？