Question

f(x)=ln(√x2+1)的导数是多少

Answer 1

y=ln(√(x^2+1)
y'=[1/√(x^2+1)]*[√(x^2+1)]'
=[1/√(x^2+1)]*(1/2)[1/√(x^2+1)]*(2x)
=[1/(x^2+1)]*x
=x/(x^2+1).