Question

若复数z满足满足z（1+i）=2，则z的虚部是______

若复数z满足满足z（1+i）=2，则z的虚部是______．

Answer 1

∵复数z满足满足z（1+i）=2，∴z=

2

1+i

=

2(1?i)

(1+i)(1?i)

=

2?2i

2

=1-i，故 z的虚部是-1，
故答案为-1．