求[(x^2-4/x^2-x-6)+(x+2/x-3)]/(x+1/x-3)
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原式=[(x+2)(x-2)/(x-3)(x+2)+(x+2)/(x-3)]×(x-3)/(x+1)
=[(x-2)/(x-3)+(x+2)/(x-3)]×(x-3)/(x+1)
=[(x-2+x+2)/(x-3)]×(x-3)/(x+1)
=[2x/(x-3)]×(x-3)/(x+1)
=2x/(x+1)
=[(x-2)/(x-3)+(x+2)/(x-3)]×(x-3)/(x+1)
=[(x-2+x+2)/(x-3)]×(x-3)/(x+1)
=[2x/(x-3)]×(x-3)/(x+1)
=2x/(x+1)
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