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1+√3tan10
=1+√3sin10/cos10
=(cos10+√3sin10)/cos10
=2sin(10+30)/cos10
=2sin40/cos10
sin50(1+√3tan10)
=(2sin40sin50)/cos10
=[cos(50-40)-cos(50+40)]/cos10
=cos10/cos10
=1
=1+√3sin10/cos10
=(cos10+√3sin10)/cos10
=2sin(10+30)/cos10
=2sin40/cos10
sin50(1+√3tan10)
=(2sin40sin50)/cos10
=[cos(50-40)-cos(50+40)]/cos10
=cos10/cos10
=1
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