Question

用c++编写计算器程序

看到你曾经帮别人回答过编写计算器的问题，能不能把代码也借我用一下啊，我们最近也为这代码发愁呢，谢谢了！！

Answer 1

#include <iostream>using namespace std;int main(){double x,y;char z;cout<<"请输入第一个数字:"<<endl;cin>>x;cout<<"请输入第二个数字:"<<endl;cin>>y;cout<<"请输入输入运算符号(+、-、*、/):"<<endl;cin>>z;cout.precision(7);switch(z){case '+':cout<<"结果:"<< x+y<<endl;break;case '-':cout<<"结果:"<< x-y<<endl;break;case '*':cout<<"结果:"<< x*y<<endl;break;case '/':cout<<"结果:"<< x/y<<endl;break;default:cout<<"请输入正确的运算符号。"<<endl;}system("pause");return 0;}

Answer 2

Calculate.h

#include <iostream>
#include <math.h>
#define PI 3.1415926
using namespace std;

class Calculate{
private:
float xx,yy,zz;
public:
Calculate(){}
Calculate(float x,float y,float z){
this->xx=x;
this->yy=y;
this->zz=z;
}

float setxx(float a){
this->xx=a;
return 0;
}

float setyy(float b){
this->yy=b;
return 0;
}

float setzz(float c){
this->zz=c;
return 0;
}

float getxx(float a){
return a;
}

float getyy(float b){
return b;
}

float getzz(float c){
return c;
}

void Add(){
float a,b,c;
cout << "请输入要相加的两个数："<<endl;
cin>>a>>b;
c=a+b;
cout << "c="<<c<<endl;

}

void Minus(){
float a,b,c;
cout << "请输入要相减的两个数："<<endl;
cin>>a>>b;
c=a-b;
cout << "c="<<c<<endl;
}

void Multip(){
float a,b,c;
cout<<"请输入要相乘的两个数："<<endl;
cin>>a>>b;
c=a*b;
cout << "结果为："<<c<<endl;
}

void Divid(){
float a,b,c;
cout<<"请输入被除数和除数："<<endl;
cin>>a>>b;

if(b==0) {
cout<<"除数不能为0，请重新输入除数"<<endl;
cin>>b;}
c=a/b;
cout << "结果为："<<c<<endl;
}

void Sin(){
float x,i;
const double HD=PI/180;
cout<<"请输入您要计算的角度："<<endl;
cin>>i;
cout<<"x\tsin(x)"<<endl;
cout<<i<<"\t"<<sin(i*HD)<<endl;
}

void Cos(){
float x,i;
const double HD=PI/180;
cout<<"请输入您要计算的角度："<<endl;
cin>>i;
cout<<"x\tcos(x)"<<endl;
cout<<i<<"\t"<<cos(i*HD)<<endl;
}

void Asin(){
float x,i;
const double D=180/PI;
cout<<"请输入要计算的反正弦的值："<<endl;
cin>>i;
cout<<"x\tasin(x)"<<endl;
cout<<i<<"\t"<<asin(i)*D<<endl;
}

void Acos(){
float x,i;
const double D=180/PI;
cout<<"请输入要计算的反余弦的值："<<endl;
cin>>i;
cout<<"x\tacos(x)"<<endl;
cout<<i<<"\t"<<acos(i)*D<<endl;
}

};

主函数在下边，都放在这放不了。o(∩_∩)o...