Jquery easyui 怎么得到datagrid 里面的值和传到后台
1个回答
展开全部
您好:得到datagrid的数据有好几种。
getData() Return the loaded data.
getRows() Return the current page rows.
getFooterRows() Return the footer rows.
getRowIndex() Return the specified row index, the row parameter can be a row record or an id field value.
getChecked() Return all rows where the checkbox has been checked. This method is available since version 1.3.
getSelected() Return the first selected row record or null.
getSelections() Return all selected rows, when no record selected, am empty array will return.
传到后台的话直接ajax提交即可。
getData() Return the loaded data.
getRows() Return the current page rows.
getFooterRows() Return the footer rows.
getRowIndex() Return the specified row index, the row parameter can be a row record or an id field value.
getChecked() Return all rows where the checkbox has been checked. This method is available since version 1.3.
getSelected() Return the first selected row record or null.
getSelections() Return all selected rows, when no record selected, am empty array will return.
传到后台的话直接ajax提交即可。
本回答被提问者和网友采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询