Question

用c++把数字转换成字符串

输出BarPlot – A Simple Bar Graph Plotter:
Input a number in range [0 50] or a negative number to terminate:
----------------------------------------------- | Enter Number: 6
| ====+> 6 | Enter Number: 12
| ====+====|=> 12 | Enter Number: 50
| ====+====|====+====|====+====|====+====|====+====> 50 | Enter Number: 53
| ERROR: 53 is not in acceptable range. | Enter Number: 33
| ====+====|====+====|====+====|==> 33 | Enter Number: 0
| 0
| Enter Number: 5
| ====> 5 | Enter Number: -1 ------------------------------------------------
BarPlot – End Plot by User Request

Answer 1

void  fun(char* pstr)
{//注意：该函数只针对字符串中全是数字的情况，如果有其它字符，请重新判断处理

 if(NULL == pstr)
    return;
    int strlength = strlen(pstr);
  if(strlength <= 0)
   return;
  int *arr = new int[strlength+1];
 memset(arr,0, strlength + 1);
  int i = 0;
   while(*(pstr + i)  != '\0)
   {
      arr[i] = *(pstr + i)  - '0';
     ++i;
    }   
  for(i =0; i <= strlength)
   cout<<arr[i]<<" ";
 cout<<endl;
}