因式分解谢谢啦啊啊
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5.
2x²+4x+2-2y²
=2[(x²+2x+1)-y²]
=2[(x+1)²-y²]
=2(x+y+1)(x-y+1)
7.
x²-3xy+2y²+x-y
=(x²-3xy+2y²)+(x-y)
=(x-y)(x-2y)+(x-y)
=(x-y)(x-2y+1)
9.
x²-4xy+4y²-2x+4y-3
=(x²-4xy+4y²)-2(x-2y)-3
=(x-2y)²-2(x-2y)-3
=(x-2y+1)(x-2y-3)
2x²+4x+2-2y²
=2[(x²+2x+1)-y²]
=2[(x+1)²-y²]
=2(x+y+1)(x-y+1)
7.
x²-3xy+2y²+x-y
=(x²-3xy+2y²)+(x-y)
=(x-y)(x-2y)+(x-y)
=(x-y)(x-2y+1)
9.
x²-4xy+4y²-2x+4y-3
=(x²-4xy+4y²)-2(x-2y)-3
=(x-2y)²-2(x-2y)-3
=(x-2y+1)(x-2y-3)
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5，2x²+4x+2-y
=2(x+1)²-2y²
=2[(x+1)²-y²]
=2(x+1-y)(x+1+y)
6，x²-3xy+2y²+x-y
=(x-2y)(x-y)+(x-y)
=(x-2y+1)(x-y)
=2(x+1)²-2y²
=2[(x+1)²-y²]
=2(x+1-y)(x+1+y)
6，x²-3xy+2y²+x-y
=(x-2y)(x-y)+(x-y)
=(x-2y+1)(x-y)
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