Question

数学题求教！！！！！！！！！！

计算
(x+3/x+2)+(x+4/x+3)=(x+5/x+4)+(x+2/x+1)
（x+2分之x+3） 加（x+3分之x+4）=（x+4分之x+5）加（x+1分之x+2）过程，我知道x=-2分之5 不知道过程

Answer 1

(x+3)/(x+2)+(x+4)/(x+3)=(x+5)/(x+4)+(x+2)/(x+1)
(x+2+1)/(x+2)+(x+3+1)/(x+3)=(x+4+1)/(x+4)+(x+1+1)/(x+1)
[1+1/(x+2)]+[1+1/(x+3)]=[1+1/(x+4)]+[1+1/(x+1)]
1/(x+2)+1/(x+3)=1/(x+4)+1/(x+1)
(x+3+x+2)/(x+3)(x+2)=(x+1+x+4)/(x+1)(x+4)
(2x+5)/(x^2+5x+6)-(2x+5)/(x^2+5x+4)=0
(2x+5)[1/(x^2+5x+6)-1/(x^2+5x+4)]=0
∵x^2+5x+6≠x^2+5x+4
∴1/(x^2+5x+6)-1/(x^2+5x+4)≠0
∴2x+5=0
∴x=-5/2
将x=-5/2代入原方程：
解得：2=2≠0
∴x=-5/2是方程的解

Answer 2

2