Question

线性代数 齐次方程求解，要过程啊(x后的是下标）~~

3x1+4x2-5x3+7x4=0
2x1-3x2+3x3-2x4=0
4x1+11x2-13x3+16x4=0
7x1-2x2+x3+3x4=0

Answer 1

3 4 -5 7
2 -3 3 -2
4 11 -13 16
7 -2 1 3
=1 7 -8 9 =1 7 -8 9 =1 7 -8 9 =1 7 -8 9 =1 24 0 0
2 -3 3 -2 0 -17 19 -20 0 -17 19 -20 0 -17 -8 9 0 -17 -8 -9
4 11 -13 16 0 -17 19 -20 0 -17 19 -20 0 0 0 0 0 0 0 0
7 -2 1 3 0 -51 57 -60 0 0 0 0 0 0 0 0 0 0 0 0
即x1+24x2=0 所以，x1=-24x2 令，x3=c1 所以x1=(192/17)c1- (216/17)c2
-17x2-8x3+9x4=0 x2=-(8/17)x3+(9/17)x4 x4=c2 x2=(-8/17)c1+ (9/17)c2
x3=c1
x4=c2
即为此方程的解