Question

999又9分之8÷（一1又9分之1）+（一2分之3）ⅹ（一5分之3）？

Answer 1

999又8/9÷(–1又1/9)
+(–2/3)×(–3/5)
(999+8/9)÷(–10/9)+2/5
=(999+8/9)×(–9/10)+2/5
=999×(-0.9)+8/9×(-9/10)+2/5
=–899.1–0.8+0.4
=–899.5

Answer 2

原式=999*(-10/9)+9/8*(-10/9)+(2/3)*(5/3)
=(10/9)*(1-999-9/8)
=(10/9)*(-999+9/1)
=-10/8991+10/1
=-10/8990
=-899

Answer 3

(999+8/9)/(-1-1/9)+(-3/2)×(-3/5)
=(999+8/9)x (-9/10)+(-3/2)×(-3/5)
=-999×0.9-0.8+0.9
=0.9×(-999+1)-0.8
=0.9×(-1000+2)-0.8
=-900+1.8-0.8
=-899

Answer 4

999又9分之8÷（一1又9分之1）+（一2分之3）ⅹ（一5分之3）？
= -999又9分之8÷10/9+3/2x3/5
=-999又8/9x9/10+2/5
=（1/9-1000）x9/10+2/5
=1/9x9/10-1000x9/10+2/5
=1/10+2/5-900
=1/2-900
=-899.5

Answer 5

999又8/9÷(-1又1/9)+(-3/2)×(-3/5)
=(1000-1/9)÷(-10/9)+9/10
=(1000-1/9)×(-9/10)+9/10
=1000×(-9/10)-1/9×(-9/10)+9/10
=-900+1/10+9/10
=-899