Question

java计算时间差

得到两个时间，希望您能给出最简洁的方法计算出几时几分几秒？

Answer 1

现在是2004-03-26 13：31：40
过去是：2004-01-02 11：30：24
要获得两个日期差，差的形式为：XX天XX小时XX分XX秒

方法一：
DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

try
{
Date d1 = df.parse("2004-03-26 13:31:40");
Date d2 = df.parse("2004-01-02 11:30:24");
long diff = d1.getTime() - d2.getTime();
long days = diff / (1000 * 60 * 60 * 24);
}
catch (Exception e)
{
}

方法二：
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
java.util.Date now = df.parse("2004-03-26 13:31:40");
java.util.Date date=df.parse("2004-01-02 11:30:24");
long l=now.getTime()-date.getTime();
long day=l/(24*60*60*1000);
long hour=(l/(60*60*1000)-day*24);
long min=((l/(60*1000))-day*24*60-hour*60);
long s=(l/1000-day*24*60*60-hour*60*60-min*60);
System.out.println(""+day+"天"+hour+"小时"+min+"分"+s+"秒");

方法三：
SimpleDateFormat dfs = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
java.util.Date begin=dfs.parse("2004-01-02 11:30:24");
java.util.Date end = dfs.parse("2004-03-26 13:31:40");
long between=(end.getTime()-begin.getTime())/1000;//除以1000是为了转换成秒

long day1=between/(24*3600);
long hour1=between%(24*3600)/3600;
long minute1=between%3600/60;
long second1=between%60/60;
System.out.println(""+day1+"天"+hour1+"小时"+minute1+"分"+second1+"秒");

====================================================

java 比较时间大小

String s1="2008-01-25 09:12:09";
String s2="2008-01-29 09:12:11";
java.text.DateFormat df=new java.text.SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
java.util.Calendar c1=java.util.Calendar.getInstance();
java.util.Calendar c2=java.util.Calendar.getInstance();
try
{
c1.setTime(df.parse(s1));
c2.setTime(df.parse(s2));
}catch(java.text.ParseException e){
System.err.println("格式不正确");
}
int result=c1.compareTo(c2);
if(result==0)
System.out.println("c1相等c2");
else if(result<0)
System.out.println("c1小于c2");
else
System.out.println("c1大于c2");

Answer 2

现在是2004-03-26 13：31：40
过去是：2004-01-02 11：30：24
要获得两个日期差，差的形式为：XX天XX小时XX分XX秒

方法一：
DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

try
{
   Date d1 = df.parse("2004-03-26 13:31:40");
   Date d2 = df.parse("2004-01-02 11:30:24");
   long diff = d1.getTime() - d2.getTime();
   long days = diff / (1000 * 60 * 60 * 24);
}
catch (Exception e)
{
}

方法二：
  SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
  java.util.Date now = df.parse("2004-03-26 13:31:40");
  java.util.Date date=df.parse("2004-01-02 11:30:24");
  long l=now.getTime()-date.getTime();
  long day=l/(24*60*60*1000);
  long hour=(l/(60*60*1000)-day*24);
  long min=((l/(60*1000))-day*24*60-hour*60);
  long s=(l/1000-day*24*60*60-hour*60*60-min*60);
  System.out.println(""+day+"天"+hour+"小时"+min+"分"+s+"秒");

方法三：
  SimpleDateFormat dfs = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
  java.util.Date begin=dfs.parse("2004-01-02 11:30:24");
  java.util.Date end = dfs.parse("2004-03-26 13:31:40");
  long between=(end.getTime()-begin.getTime())/1000;//除以1000是为了转换成秒

  long day1=between/(24*3600);
  long hour1=between%(24*3600)/3600;
  long minute1=between%3600/60;
  long second1=between%60/60;
  System.out.println(""+day1+"天"+hour1+"小时"+minute1+"分"+second1+"秒");

Answer 3

比如：现在是2004-03-26 13：31：40

过去是：2004-01-02 11：30：24

我现在要获得两个日期差，差的形式为：XX天XX小时XX分XX秒

方法一：

DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

try{ Date d1 = df.parse("2004-03-26 13:31:40");

Date d2 = df.parse("2004-01-02 11:30:24");

long diff = d1.getTime() - d2.getTime();

long days = diff / (1000 * 60 * 60 * 24)}

catch (Exception e){}

方法二：

SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

java.util.Date now = df.parse("2004-03-26 13:31:40");

java.util.Date date=df.parse("2004-01-02 11:30:24");

long l=now.getTime()-date.getTime();

long day=l/(24*60*60*1000);

long hour=(l/(60*60*1000)-day*24);

long min=((l/(60*1000))-day*24*60-hour*60);

long s=(l/1000-day*24*60*60-hour*60*60-min*60);

System.out.println(""+day+"天"+hour+"小时"+min+"分"+s+"秒");

方法三：

SimpleDateFormat dfs = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

java.util.Date begin=dfs.parse("2004-01-02 11:30:24");

java.util.Date end = dfs.parse("2004-03-26 13:31:40");

long between=(end.getTime()-begin.getTime())/1000;//除以1000是为了转换成秒

long day1=between/(24*3600);

long hour1=between%(24*3600)/3600;

long minute1=between%3600/60;

long second1=between%60/60;

System.out.println(""+day1+"天"+hour1+"小时"+minute1+"分"+second1+"秒");

====================================================

java 比较时间大小

String s1="2008-01-25 09:12:09";

String s2="2008-01-29 09:12:11";

java.text.DateFormat df=new java.text.SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

java.util.Calendar c1=java.util.Calendar.getInstance();

java.util.Calendar c2=java.util.Calendar.getInstance();

try{c1.setTime(df.parse(s1));c2.setTime(df.parse(s2));}catch(java.text.ParseException e){

System.err.println("格式不正确");}

int result=c1.compareTo(c2);

if(result==0)

System.out.println("c1相等c2");

else if(result<0)

System.out.println("c1小于c2");

else

Answer 4

public static String diff(String strDate, String pattern){
	String ret = "";
	try{
		Date now = new Date();
		
		SimpleDateFormat sdf = new SimpleDateFormat(pattern);
		Date tmp = sdf.parse(strDate);
		
		if(tmp.after(now)){
			return "时间超过当前时间";
		}
		long s = (now.getTime() - tmp.getTime()) / 1000;
		long count = 0;
		if((count = s / (3600 * 24 * 365)) > 0){
			ret = count + "年前";
		}else if((count = s / (3600 * 24 * 30)) > 0){
			ret = count + "月前";
		}else if((count = s / 3600 * 24) > 0){
			ret = count + "天前";
		}else if((count = s / 3600) > 0){
			ret = count + "小时前";
		}else if((count = s / 60) > 0){
			ret = count + "分钟前";
		}else{
			ret = "刚刚";
		}
	}catch (Exception e) {
	}
	
	return ret;
}

以上算法月份是按30天来算，年以365天来算的。