设函数f(x)=(x-1)(x-2)...(x-100)(x>100),求F'(X)
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lnf(x)=ln(x-1)+ln(x-2).+ln(x-100)
两侧求导得：f'(x)/f(x)=1/(x-1)+1/(x-2)+...+1/(x-100)
f'(x)=(x-1)(x-2)...(x-100)[1/(x-1)+1/(x-2)+...+1/(x-100)]
两侧求导得：f'(x)/f(x)=1/(x-1)+1/(x-2)+...+1/(x-100)
f'(x)=(x-1)(x-2)...(x-100)[1/(x-1)+1/(x-2)+...+1/(x-100)]
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