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求值域 y=(1+sinx)/(2+sinx)
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y
= (1 + sinx)/(2 + sinx)
= (2 + sinx - 1)/(2 + sinx)
= 1 - 1/(2 + sinx)
-1 ≤ sinx ≤ 1
1 ≤ 2 + sinx ≤ 3
1/3 ≤ 1/(2 + sinx) ≤ 1
-1 ≤ -1/(2 + sinx) ≤ -1/3
0 ≤ 1 - 1/(2 + sinx) ≤ 2/3
所以值域是 [0 , 2/3]
= (1 + sinx)/(2 + sinx)
= (2 + sinx - 1)/(2 + sinx)
= 1 - 1/(2 + sinx)
-1 ≤ sinx ≤ 1
1 ≤ 2 + sinx ≤ 3
1/3 ≤ 1/(2 + sinx) ≤ 1
-1 ≤ -1/(2 + sinx) ≤ -1/3
0 ≤ 1 - 1/(2 + sinx) ≤ 2/3
所以值域是 [0 , 2/3]
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