第四题!谢谢!
1个回答
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lim(3x-sin3x)/[(1-cosx)ln(1+2x)=lim(3x-sin3x)/[2sin²(x/2)ln(1+2x)]
x→0
=lim(3-3cos3x)/[2sin(x/2)cos(x/2)ln(1+2x)+4sin²(x/2)/(1+2x)]
x→0
=lim 6sin²(3x/2)/[sinxln(1+2x)+2sin²(x/2))]
x→0
=lim (27x²/2)/[xln(1+2x)+x²/2]
x→0
=lim (27/2)/[ln(1+2x)/x+1/2]
=27/(2+√e)
x→0
=lim(3-3cos3x)/[2sin(x/2)cos(x/2)ln(1+2x)+4sin²(x/2)/(1+2x)]
x→0
=lim 6sin²(3x/2)/[sinxln(1+2x)+2sin²(x/2))]
x→0
=lim (27x²/2)/[xln(1+2x)+x²/2]
x→0
=lim (27/2)/[ln(1+2x)/x+1/2]
=27/(2+√e)
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