Question

汇编语言 这句为什么会出错

程序是这样的
DATA SEGMENT
ORG 100H
BUF1 DB 256 DUP(?)
COUNT EQU $-BUF1
DATA ENDS
CODE SEGMENT
ASSUME CS:CODE,DS:DATA
START: MOV AX,DATA
MOV DS,AX
MOV SI,OFFSET BUF1
MOV CX,COUNT
XOR AL,AL
NEXT: MOV [SI],AL
INC AL
INC SI
LOOP NEXT
MOV AH,4CH
INT 21H
CODE ENDS
END START
点运行提示我
unterminated string: 256 DUP(")
怎么解决？
谢谢

Answer 1

我用MASM5.0编译正常通过.....
运行结果也正常!

E:\masm>masm 1204.asm
Microsoft (R) Macro Assembler Version 5.00
Copyright (C) Microsoft Corp 1981-1985, 1987. All rights reserved.

Object filename [1204.OBJ]: Source listing [NUL.LST]: Cross-reference [NUL.CRF]:
50796 + 450484 Bytes symbol space free

0 Warning Errors
0 Severe Errors

E:\masm>link 1204

Microsoft (R) Overlay Linker Version 3.60
Copyright (C) Microsoft Corp 1983-1987. All rights reserved.

Run File [1204.EXE]: List File [NUL.MAP]: Libraries [.LIB]: LINK : warning L4021: no stack segment

C:\>DEBUG 1204.EXE
-g5

AX=0B56 BX=0000 CX=0218 DX=0000 SP=0000 BP=0000 SI=0000 DI=0000
DS=0B56 ES=0B46 SS=0B56 CS=0B76 IP=0005 NV UP EI PL NZ NA PO NC
0B76:0005 BE0001 MOV SI,0100
-d100

0B56:0100 00 00 00 00 00 00 00 00-00 00 00 00 00 00 00 00 ................
0B56:0110 00 00 00 00 00 00 00 00-00 00 00 00 00 00 00 00 ................
0B56:0120 00 00 00 00 00 00 00 00-00 00 00 00 00 00 00 00 ................
0B56:0130 00 00 00 00 00 00 00 00-00 00 00 00 00 00 00 00 ................
0B56:0140 00 00 00 00 00 00 00 00-00 00 00 00 00 00 00 00 ................
0B56:0150 00 00 00 00 00 00 00 00-00 00 00 00 00 00 00 00 ................
0B56:0160 00 00 00 00 00 00 00 00-00 00 00 00 00 00 00 00 ................
0B56:0170 00 00 00 00 00 00 00 00-00 00 00 00 00 00 00 00 ................
-g14

Program terminated normally
-d100

0B56:0100 00 01 02 03 04 05 06 07-08 09 0A 0B 0C 0D 0E 0F ................
0B56:0110 10 11 12 13 14 15 16 17-18 19 1A 1B 1C 1D 1E 1F ................
0B56:0120 20 21 22 23 24 25 26 27-28 29 2A 2B 2C 2D 2E 2F !"#$%&'()*+,-./
0B56:0130 30 31 32 33 34 35 36 37-38 39 3A 3B 3C 3D 3E 3F 0123456789:;<=>?
0B56:0140 40 41 42 43 44 45 46 47-48 49 4A 4B 4C 4D 4E 4F @ABCDEFGHIJKLMNO
0B56:0150 50 51 52 53 54 55 56 57-58 59 5A 5B 5C 5D 5E 5F PQRSTUVWXYZ[\]^_
0B56:0160 60 61 62 63 64 65 66 67-68 69 6A 6B 6C 6D 6E 6F `abcdefghijklmno
0B56:0170 70 71 72 73 74 75 76 77-78 79 7A 7B 7C 7D 7E 7F pqrstuvwxyz{|}~.
-d
0B56:0180 80 81 82 83 84 85 86 87-88 89 8A 8B 8C 8D 8E 8F ................
0B56:0190 90 91 92 93 94 95 96 97-98 99 9A 9B 9C 9D 9E 9F ................
0B56:01A0 A0 A1 A2 A3 A4 A5 A6 A7-A8 A9 AA AB AC AD AE AF ................
0B56:01B0 B0 B1 B2 B3 B4 B5 B6 B7-B8 B9 BA BB BC BD BE BF ................
0B56:01C0 C0 C1 C2 C3 C4 C5 C6 C7-C8 C9 CA CB CC CD CE CF ................
0B56:01D0 D0 D1 D2 D3 D4 D5 D6 D7-D8 D9 DA DB DC DD DE DF ................
0B56:01E0 E0 E1 E2 E3 E4 E5 E6 E7-E8 E9 EA EB EC ED EE EF ................
0B56:01F0 F0 F1 F2 F3 F4 F5 F6 F7-F8 F9 FA FB FC FD FE FF ................

-q

Answer 2

DUP申请数组应该是中括号，而不是圆括号

DUP[?]

还有不明白的可以找我。

Answer 3

实际运行了一下，没问题

Answer 4

定义的太长了，

Answer 5

是在哪个环境下运行？