Question

解方程sin（3x-π/6）=-根号2/2 要有详细解题过程

Answer 1

sin(3X-π/6）=sin3π/4=sin7π/4=-√2/2
即3X-π/6=2Kπ+3π/4=2Kπ+7π/4，
3X=2Kπ+11π/12,3X=2Kπ+23π12，所以X=2Kπ/3+11π36，X=2Kπ/3+23π36

Answer 2

sin(3x+π/6)=sin(4π/3)=sin(5π/3)
即3x+π/6=2kπ+4π/3，3x+π/6=2kπ+5π/3
3x=2kπ+7π/6，3x=2kπ+3π/2
x=2kπ/3+7π/18，x=2kπ/3+π/2