Question

这道题怎么解？？？ 要详细解法及答案！！！！

Answer 1

AB=AE -> △ADE绕A点旋转，使E点与B点重合，D点转至D'
-> AD=AD'，BD'=DE，∠D'BA=∠AED，∠BD'A=∠ADE
∠ABC+∠AED=180°
-> ∠ABC+∠D'BA=∠ABC+∠AED=180°
-> D'，B，C三点在同一直线上
BC+DE=CD，BD'=DE
-> CD'=BC+BD'=BC+DE=CD

连接DD'，CD'=CD
-> ∠CD'D=∠CDD'
AD=AD'
-> ∠AD'D=∠ADD'
∠BD'A=∠CD'D+∠AD'D
∠ADC=∠CDD'+∠ADD'
-> ∠BD'A=∠ADC
∠BD'A=∠ADE
-> ∠ADC=∠ADE
-> AD平分角CDE