Question

三维电极处理含铜废水最后沉淀怎么去除

Answer 1

(1) using Fe as the electrodes for electrolysis, anode electrode, the electrode itself is active, oxidized betatopic, Fe-2e- one Fe2+, the cathode is the reduction of cations in electronics, 2H++2e- one H2 decrease, so the answer is: one is Fe-2e- Fe2+; 2H++2e- H2 =
one (2); Cr2O72- has strong oxidation, the oxidation of ferrous iron ion, its reaction was reduced to 2Cr3+, is the essence of 6Fe2++Cr2O72-+14H+: one is 6Fe3++2Cr3++7H2O
, so the answer is: Cr2O72-+6Fe2++14H+=2Cr3++6Fe3++7H2O;
(3) 2H++2e- H2 increase occurred in one reaction pool cathode, Cr2O72- and Fe2+ reaction, will consume a large number of H+, the solution pH increased, the Fe3+, the hydrolysis of Cr3+ and eventually into the Fe (OH) 3, Cr (OH) 3
precipit因此，答案是：用电解溶液。酸度逐渐减弱，碱度逐渐增大。最后，Cr（OH）3和Fe（OH）- 3形成