Question

函数y=2sin（x+π/3），x属于[π/6，π/2]的值域

Answer 1

解：
π/6<=x<=π/2
π/2<=x+π/3<=5π/6
1/2<=sin（x+π/3)<=1
1<=2sin（x+π/3)<=2
所以函数值域为[1,2]

Answer 2

π/6≤x≤π/2
π/2≤x+π/3≤5π/6
1/2≤sin(x+π/3)≤1≤
1≤2sin(x+π/3)≤2

Answer 3

先画y=sinX的图像，再横坐标不变，纵坐标变为原来的2倍，再向左平移π/3个单位，然后找x属于[π/6，π/2]的值域