Question

怎么用python 的多线程打印1到1000的数字

Answer 1

#coding=utf-8
import threading
from time import ctime,sleep
 
res = []
def add(list_num):
    print list_num
if __name__ == '__main__':
    threads = []
    list_num = []
    for i in range(1,101):
        if len(list_num)==30:
            t = threading.Thread(target=add,args=(list_num,))
            threads.append(t)
            list_num=[]
        else:
       行升腊     list_num.append(i)
    if list_num:
        t = threading.Thread(target=add,args=(list_num,))
   笑毁     threads.append(t)
    for t in threads:
      档滑  t.setDaemon(True)
        t.start()