Question

解方程:(5y+2)/7—(3+2y)/3—(3y-14)/12=1

上面打错了。除以12应该是除以2

Answer 1

(5y+2)/7—(3+2y)/3—(3y-14)/2=1

同时乘以42
6（5y+2）-14(3+2y)-21(3y-14)=42
30y+12-42-28y-63y+294-42=0
-61y+222=0
y=222/61

Answer 2

12(5y+2)-28(3+2y)-7(3y-14)=84
60y+24-84-56y-21y-28=84
y=-172\17