要这些题的过程和答案,谢谢!
1个回答
2018-07-11
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A. 1又3/25+[(1.5+2又2/3)÷3又3/4-0.4]+8又8/9 =28/25+[(9/6+16/6)÷15/4-0.4]+80/9 =28/25+[(9/6+16/6)÷15/4-0.4]+80/9 =28/25+[10/9-10/25]+80/9 =10+18/25 =10又18/25 B. [(15/28-11/36)×21/29+6又2/7÷16/21]÷16又1/2 =[45/(4×29)-77/(12×29)+(44×21)/(7×16)]÷33/2 =[1/6+33/4]÷33/2 =1/99+1/2 =101/198 C. 1-[(2又1/2-1又1/3)÷1又1/6]÷4又1/2+2又1/3 =1-[7/6÷7/6]÷9/2+7/3 =1-2/9+21/9 =1+19/9 =3又1/9 D.[1÷(3.1-3.09)]÷(1/3+0.8+8/15) =100÷5/3 =60 E. 1998×1999-1995×2002 =1998×1999-(1998-3)×(1999+3) =1998×1999-(1998×1999-3×1999+1998×3-9) =1998×1999-(1998×1999-12) =12
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