求换算过程！！！
(log3/(2log2)+log3/(3log2))(log2/log3+log2/(2log3))=5/6*log3/log2*3/2*log2/log3...
(log3/(2log2)+log3/(3log2))(log2/log3+log2/(2log3))
=5/6*log3/log2*3/2*log2/log3 展开
=5/6*log3/log2*3/2*log2/log3 展开
展开全部
[log3/(2log2)+log3/(3log2)][log2/log3+log2/(2log3)]
=[(1/2)log3/(log2)+(1/3)log3/(log2)][log2/log3+(1/2)log2/(log3)]
=[(1/2+1/3)log3/(log2)][(1+1/2)log2/(log3)]
=(5/6)*[log3/(log2)][(3/2)log2/(log3)]
=(5/6)*(3/2)
=5/4
=[(1/2)log3/(log2)+(1/3)log3/(log2)][log2/log3+(1/2)log2/(log3)]
=[(1/2+1/3)log3/(log2)][(1+1/2)log2/(log3)]
=(5/6)*[log3/(log2)][(3/2)log2/(log3)]
=(5/6)*(3/2)
=5/4
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