Question

t^2-2t-1=0求t

t的2次方减2t减1等于0，求t的值，要求写出全过程，里面的公式原理等，越详细越好

Answer 1

t²-2t-1 = 0
t²-2t+1 = 2
(t-1)² = 2
t-1 = ±√2
t = 1±√2

满意请采纳。

Answer 2

t² - 2t - 1 = 0
移项，t² - 2t = 1
左右两边同时加上 1，t² - 2t +1 = 1 +1
（t + 1 ）² =2
开方，t +1 = ±√2
t1 = 1 +√2
t2 = 1 - √2

Answer 3

t^2-2t-1=0
t^2-2t+1=2
(t-1)^2=2
t=1±√2

Answer 4