第11题怎么做?
2个回答
展开全部
cosider
cos(A-B)=cosA.cosB+sinA.sinB (1)
cos(A+B)=cosA.cosB-sinA.sinB (2)
(1)-(2)
sinA.sinB= (1/2)[cos(A-B)-cos(A+B)]
A=x+y (3)
B=x-y (4)
sin(x+y).sin(x-y)
= (1/2)[cos(2y)-cos(2x)]
= (1/2){[1-2(siny)^2]-[1-2(sinx)^2]}
=(sinx)^2 -(siny)^2
cos(A-B)=cosA.cosB+sinA.sinB (1)
cos(A+B)=cosA.cosB-sinA.sinB (2)
(1)-(2)
sinA.sinB= (1/2)[cos(A-B)-cos(A+B)]
A=x+y (3)
B=x-y (4)
sin(x+y).sin(x-y)
= (1/2)[cos(2y)-cos(2x)]
= (1/2){[1-2(siny)^2]-[1-2(sinx)^2]}
=(sinx)^2 -(siny)^2
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